# Line slope calculator 3x+5y=34

**Straight line given by points A[3; 5] and B[8; 2]**

## Calculation:

**Slope-intercept form of line:**y = -0.6x+6.8

**Canonical form of the line equation:**3x+5y-34 = 0

**Parametric form of the line equation:**

x = 5t+3

y = -3t+5 ; t ∈ R

**Slope:**m = -0.6

**Slope angle of line: φ =**-30°57'50″ = -0.5404 rad

**X intercept:**x

_{0}= 11.3333

**Y intercept:**y

_{0}= q = 6.8

**Distance line from the origin:**d

_{0}= 5.831

**The length of the segment AB: |AB| =**5.831

**Vector: AB =**(5; -3)

**Normal vector: n =**(3; 5)

**Midpoint of the segment AB: M =**[5.5; 3.5]

**Perpendicular Bisector equation:**5x-3y-17 = 0

**Vector OA = (3; 5) ; |OA| = 5.831**

**Vector OB = (8; 2) ; |OB| = 8.2462**

**Scalar product OA .OB = 34**

**Angle ∠ AOB = 45° = 0.7854 rad**