# Line slope calculator x+6y=36

**Straight line given by points A[0; 6] and B[6; 5]**

## Calculation:

**Slope-intercept form of line:**y = -0.1667x+6

**Canonical form of the line equation:**x+6y-36 = 0

**Parametric form of the line equation:**

x = 6t

y = -t+6 ; t ∈ R

**Slope:**m = -0.1667

**Slope angle of line: φ =**-9°27'44″ = -0.1651 rad

**X intercept:**x

_{0}= 36

**Y intercept:**y

_{0}= q = 6

**Distance line from the origin:**d

_{0}= 5.9184

**The length of the segment AB: |AB| =**6.0828

**Vector: AB =**(6; -1)

**Normal vector: n =**(1; 6)

**Midpoint of the segment AB: M =**[3; 5.5]

**Perpendicular Bisector equation:**6x-y-12.5 = 0

**Vector OA = (0; 6) ; |OA| = 6**

**Vector OB = (6; 5) ; |OB| = 7.8102**

**Scalar product OA .OB = 30**

**Angle ∠ AOB = 50°11'40″ = 0.8761 rad**